Question

Pure acid is to be added to a 20% acid solution to obtain 24 L of a 50% acid solution what amounts of each should be used

Answer 1

let x be the amount of 20% acid
24-x be the amount of 100% acid


100%(24-x) + 20%(x) = 50%(24)

(24-x) + .2x = 12

12 = .8x

x=15
24-x =9

~15 L of 20% acid and 9 L of 100% acid