Question

A shop owner blends three types of tea. A,B and C, in the ratio 6:4:7. If the mass of tea C in the mixture is 28kg, find the difference in the masses of the other two types of tea.

Answer 1

So because C is 28kg, and it is 7 parts in the ratio, we can say that if we divided 28 by 7 we'd get 1 part in the ratio. 28 ÷ 7 = 4. Now we just have to multiply, so A would be (4 × 6) 24kg, and B would be (4 × 4) 16kg. I hope this helps!

Answer 2

A would be 6/7 x 28kg = 24 kg
B would be 4/7 x 28kg = 16 kg
so the difference of the masses is 24 - 16 = 8kg