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Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B How many grams of A would be needed to give the same number of particles: as 7.5 grams of B? as 2.5 grams? as 12.5 grams? as 1 gram?

User Atakann
by
6.7k points

2 Answers

4 votes

Answer:

15

5

25

2

Step-by-step explanation:

(7.5gB / 5gB) * 10gA = 15gA

(2.5gB / 5gB) * 10gA = 5gA

(12.5gB / 5gB) * 10gA = 25gA

(1gB / 5gB) * 10gA = 2gA

hope it helps :)

User Aniket Bote
by
8.2k points
7 votes

Answer:

The answers are:

15gA

5gA

25gA

2gA

Step-by-step explanation:

Hello!

let's solve this!

To calculate this we have to know the data:

mass A = 10g

mass B = 5g

mass A = (7.5gB / 5gB) * 10gA = 15gA

mass A = (2.5gB / 5gB) * 10gA = 5gA

mass A = (12.5gB / 5gB) * 10gA = 25gA

mass A = (1gB / 5gB) * 10gA = 2gA

User CalloRico
by
7.4k points