Question

Helpppp D: When sodium sulfide dissociates in water, the sulfur ion reacts with water as follows: S-2 + H2O → OH- + SH- Which of the following statements is true? Na2S is a base because it ionizes to release OH-. Na2S is an acid because it is a proton donor. Na2S is a base because it increases the hydroxide concentration. none of these

Answer 1

Answer: Option (a) is the correct answer.

Step-by-step explanation:

A base is a substance that gives hydroxide ions (
`OH^(-)`) upon dissociation in water. This means that a base increases the hydroxide ion concentration in a solution.

On the other hand, an acid is a substance that gives hydrogen ions (
`H^(+)`) upon dissociation in water. This means that an acid increases the hydrogen ion concentration in a solution.

For example,
`S^(2-) + H_(2)O \rightarrow OH^(-) + SH^(-)`

Since, sodium sulfide (
`Na_(2)S`) dissociates to give hydroxide ions.

Hence, we can conclude that
`Na_(2)S` is a base because it ionizes to release
`OH^(-)`.

Answer 2

Na2S is a base because it increases the hydroxide concentration.