This time, we start from the left side.
sec^6x-tan^6x =(sec^2x)^3-(tan^2x)^3
Then, use the identity:
a^3-b^3 = (a-b)(a^2+ab+b^2)
we get (sec^2x-tan^2x)(sec^4x+sec^2x tan^2x+ tan^4x)
Since (tan^2x+1=sec^2x)
We have \((\sec^2x-\tan^2x) = 1\).
So, (sec^2x-tan^2x)(sec^4x+sec^2x tan^2x+tan^4x)
(=sec^4x+sec^2xtan^2x+tan^4x)
Then consider (sec^4x), (sec^4x = sec^2x (sec^2x) = sec^2x(tan^2x+1) = sec^2x tan^2x+ sec^2x)
Consider (tan^4x), (tan^4x = tan^2x (tan^2x) = tan^2x(sec^2x+1) = sec^2x tan^2x- tan^2x)
Substitute the two back to (sec^4x+sec^2x tan^2x+tan^4x, and simplify it.
With the help of the identity sec^2x-tan^2x = 1, you should be able to get the right side.