Question

Solve the following system of equation using the substitution method y=3x-14 ... (1)y=x-10 ... (2)

Answer 1

We have the next equations

y=3x-14 ... (1)

y=x-10 ... (2)

we will substitute the value of y of the first equation into the second equation

`3x-14=x-10`

we sum the terms with x and the terms without x

`\begin{gathered} 3x-x=-10+14 \\ 2x=4 \\ x=(4)/(2) \\ x=2 \end{gathered}`

then we substitute the value of x in the first equation

`\begin{gathered} y=3x-14=3(2)-14 \\ y=-8 \end{gathered}`

the solution of the system of equations is

x=2 , y=-8