Question

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

a. 7x + 2y = –1
b. 7x + 2y = 1
c. 14x + 4y = –1
d. 14x + 4y = 1

Answer 1

b

Explanation:

Answer 2

if the Line JK passes through points J(–3, 11) and K(1, –3), so the the equation of line JK in standard form is b. 7x + 2y = 1

proof:
for J(–3, 11), 7(-3) +2(11)=-21+22=1
for K(1, –3), 7(1) +2(-3)= 7-6=1