Register

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form? a. 7x + 2y = –1 b. 7x + 2y = 1 c. 14x + 4y = –1 d. 14x + 4y = 1

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form? a. 7x + 2y = –1 b. 7x + 2y = 1 c. 14x + 4y = –1 d. 14x + 4y = 1
214k views
3 votes
Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

a. 7x + 2y = –1
b. 7x + 2y = 1
c. 14x + 4y = –1
d. 14x + 4y = 1

User Dexture
by
8.4k points

2 Answers

3 votes

Answer:

b

Explanation:


User Liondancer
by
8.0k points
6 votes
if the Line JK passes through points J(–3, 11) and K(1, –3), so the the equation of line JK in standard form is b. 7x + 2y = 1

proof:
for J(–3, 11), 7(-3) +2(11)=-21+22=1
for K(1, –3), 7(1) +2(-3)= 7-6=1
User Chankruze
by
8.0k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Link Copied!