Question

What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g?

12.5%

55.6%

79.8%

87.9%

Answer 1

79.8% is the percent yield of ferrous sulfide.

Step-by-step explanation:

Percentage yield :

`\frac{\text{Actual yield}}{\text{Theoretical yield}}* 100`

Actual yield of ferrous sulfide = 220.0 g

Theoretical yield of ferrous sulfide = 275.6 g

`\% (Yield)=(200.0 g)/(275.6 g)* 100`

= 79.8%

79.8% is the percent yield of ferrous sulfide.

Answer 2

The percent yield is defined as:
((Actual Yield)/(Theoretical Yield)) * 100%
Plugging in our numbers we get:
(220.0 grams)/(275.6 grams) = 0.7983
Now multiply the quotient by 100%:
0.7983 * 100% = 79.83%
Closest answer is 79.8%