Answer with explanation:
In Δ A CD and Δ A B D
AC ≅ AB⇒⇒⇒[Given]
Side,AD is Common.
You can prove two triangles Congruent either by S AS, or SSS.
So,either,→ BD=CD
or, →∠CAD=∠BAD
Δ A CD≅ Δ A B D⇒⇒⇒[S A S]
Option 1: Segment AD bisects angle CAB.
is true.