Question

What must be the acceleration of a train in order for it to stop from 11.4 seconds in a distance of 589 m? (Assume the train accelerates uniformly.) Round to 4 decimal places if necessary

Answer 1

-9.0643 m/s²

Explanation:

Given:

Distance (d) = 589 m

Time (t) = 11.4 sec

We can calculate the acceleration using the following formula:

`\begin{gathered} a=-(2s)/(t^2) \\ \\ \text{ We replacing} \\ \\ a=-(2\cdot589)/(11.4^2) \\ \\ a=-9.0643\text{ m/s}^2 \end{gathered}`

The deceleration of the train is equal to 9.0643 m/s²