Question

Help! Quick please!

An inequality is shown below: −np − 6 ≤ 3(c − 5)
Which of the following solves for n?
n ≥ − the quantity 3 times c minus 21 all over p

n ≥ − the quantity 3 times c minus 9 all over p

n ≤ − the quantity 3 times c minus 21 all over p

n ≤ − the quantity 3 times c minus 9 all over p

Answer 1

B..............
c>=3 and n<0 and p<=(9-3 c)/n

Answer 2

n ≥ − the quantity 3 times c minus 9 all over p

Explanation:

To solve inequalities you should use the same method as to solve equalities.

1. First write down the inequality:

`-np-6\leq 3(c-5)`

2. Solve the parentheses:

`-np-6\leq 3c-15`

3. Pass the independent numbers to the right side of the inequality with opposite sign and do the mathematical operations:

`-np\leq 3c-15+6\\\\-np\leq 3c-9`

4. Pass the p with the minus sign to the right side of the inequality, as p has the minus sign, the direction of the inequality changes:

`n\geq -((3c-9)/(p))`