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Help! Quick please!

An inequality is shown below: −np − 6 ≤ 3(c − 5)
Which of the following solves for n?
n ≥ − the quantity 3 times c minus 21 all over p

n ≥ − the quantity 3 times c minus 9 all over p

n ≤ − the quantity 3 times c minus 21 all over p

n ≤ − the quantity 3 times c minus 9 all over p

2 Answers

5 votes
B..............
c>=3 and n<0 and p<=(9-3 c)/n
User Renato Probst
by
8.0k points
7 votes

Answer:

n ≥ − the quantity 3 times c minus 9 all over p

Explanation:

To solve inequalities you should use the same method as to solve equalities.

1. First write down the inequality:


-np-6\leq 3(c-5)

2. Solve the parentheses:


-np-6\leq 3c-15

3. Pass the independent numbers to the right side of the inequality with opposite sign and do the mathematical operations:


-np\leq 3c-15+6\\\\-np\leq 3c-9

4. Pass the p with the minus sign to the right side of the inequality, as p has the minus sign, the direction of the inequality changes:


n\geq -((3c-9)/(p))

User Rakesh Gourineni
by
7.9k points