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What is the solution to the equation 41/5 =15-(2x+3)
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What is the solution to the equation 41/5 =15-(2x+3)

User Marinos K
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(41)/(5)=15-(2x+3)\\ (41)/(5)=15-2x-3\\ (41)/(5)=12-2x|\cdot5\\ 41=60-10x\\ 10x=19\\ x=(19)/(10)
User Demobilizer
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(41)/(5)=15-(2x+3) \\\\ (41)/(5)=15-2x-3 \\\\ (41)/(5)=12^((5)-2x^((5) \\\\ 41=60-10x \\\\ 41-60=-10x \\\\ -19=-10x \\\\ 19=10x \\\\ \boxed{x=(19)/(10)}
User JustLoren
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