Question

Complete and balance the following nuclear equations by supplying the missing particle

a) 252/98Cf + 10/5 B==========> 3 1/0n + ? (The 3 is separate from 1/0n, its not 31/0n)
b)2/1H + 3/2He ======>4/2He + ?
c) 1/1H + 11/5B=======>3?
d)122/53I(This is iodine) ========>122/54 Xe + ?
e)59/26Fe=======. 0/-1e + ?

Answer 1

a) 252/98Cf & 10/5 B ==> 3 1/0n & 259/103 Lr
b) 2/1H & 3/2He ===> 4/2He & 1/1 H
c) 1/1H & 11/5B => 3 4/2He
d) 122/53 I ==> 122/54 Xe & 0/-1e- (Beta)
e) 59/26Fe ==> 0/-1e & 59/27 Co

Answer 2

Answer: The equations are given below.

Step-by-step explanation:

• For a:

`^(252)_(98)\textrm{Cf}+^(10)_5\textrm{B}\rightarrow ^A_Z\textrm{X}+3^(1)_(0)\textrm{n}`

To calculate A:

Total mass on reactant side = total mass on product side

252 + 10 = A + 3

A = 259

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

98 + 5 = Z + 0

Z = 103

The isotopic symbol of lawrencium is
`_(103)^(259)\textrm{Lr}`

• For b:

`^(2)_(1)\textrm{H}+^(3)_2\textrm{He}\rightarrow ^4_2\textrm{He}+^A_(Z)\textrm{X}`

To calculate A:

Total mass on reactant side = total mass on product side

2 + 3 = A + 4

A = 1

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

1 + 2 = Z + 2

Z = 1

The isotopic symbol of hydrogen is
`_(1)^(1)\textrm{H}`

• For c:

`^(1)_(1)\textrm{H}+^(11)_5\textrm{B}\rightarrow 3^A_(Z)\textrm{X}`

To calculate A:

Total mass on reactant side = total mass on product side

1 + 11 = A

A = 12

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

1 + 5 = Z

Z = 6

The isotopic symbol of helium is
`_(2)^(4)\textrm{He}`

• For d:

`^(122)_(53)\textrm{I}\rightarrow ^(122)_(54)\textrm{Xe}+_Z^A\textrm{X}`

To calculate A:

Total mass on reactant side = total mass on product side

122 = A

A = 122

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

53 = 54 + Z

Z = -1

The isotopic symbol of electron is
`_(-1)^(0)\textrm{e}`

• For e:

`^(59)_(26)\textrm{Fe}\rightarrow ^(0)_(-1)\textrm{e}+_Z^A\textrm{X}`

To calculate A:

Total mass on reactant side = total mass on product side

59 + 0 = A

A = 59

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

26 = -1 + Z

Z = 27

The isotopic symbol of Cobalt is
`_(27)^(59)\textrm{Co}`