Question

How many grams of nacl are required to make 500.0 ml of a 1.500 m solution?

Answer 1

43.83g of nacl are required to make 500.0 ml of a 1.500 m solution.

Answer 2

43.875 grams of NaCl are required to make 500.0 ml of a 1.500 M solution.

Step-by-step explanation:

`Moles (n)=Molarity(M)* Volume (L)`

Moles of NaCl = n

Volume of NaCl solution = 500.0 mL = 0.500 L

Molarity of the NaCl solution = 1.500 M

`n=1.500 M* 0.500 L=0.75 mol`

Mass of 0.75 moles of NaCl:

0.75 mol × 58.5 g/mol=43.875 g

43.875 grams of NaCl are required to make 500.0 ml of a 1.500 M solution.