Question

in the reaction 3H2+N2--> NH3,what coefficient should be placed in front of NH3 to balance the reaction?

Answer 1

The best way to solve this is to list all the elements out and count them.

Count subscripts first (if there is no subscript then there is 1 atom)
Then multiply by the coefficients
To balance write a coefficient and multiply

3H2+N2--> NH3

H 2 x 3 = 6 H 3 (x2) = 6
N 2 N 1 (x2) = 2


Your answer is 2 . . . to balance this equation you will need a coefficient of 2

Answer 2

2

Step-by-step explanation:

To balance the equation there must be the same numbers of atoms at the left side and at the right side. So, at the left side we have:

6 atoms of H (3 x 2)

2 atoms of N (1 x 2)

And at the right side we have:

1 atom of N (1 x 1)

3 atoms of HN (1 x 3)

If you multiply these last by 2, you will have:

2 atoms of N (2 x 1)

6 atoms of H (2 x 3)

Then, the numbers of atoms of H and N at the left side is equal to the numbers of atoms of H and N at the right side. The balanced equation is:

3H2+N2--> 2NH3