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What is the average kinetic energy of 1 mole of gas at 102 degree celsius

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R= 8.314 J/mol K T= 273 + 102 = 375K

= (3/2) x 8.314 x 375 = 4680 J/mol
User Delark
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Answer:

The average kinetic energy of the gas is 4.678 kJ/mol.

Step-by-step explanation:

Average kinetic energy of the gas id defined as measure of an average kinetic energy possessed by each particle of the gas.

It is given as:


K=(3)/(2)RT (Average kinetic energy per mole)


K=(3)/(2)kT (Average kinetic energy per molecule)

R = Universals gas constant
8.314 J /mol K

T = temperature of the gas

k = Boltzmann constant =
1.38* 10^(-23) J/K

The average kinetic energy of 1 mole of gas at 102°C:

T = 102°C = 375.15 K[/tex]


K=(3)/(2)* 8.314 J/mol K* 375.15 K=4,678.49 J/mol=4.678 kJ/mol

The average kinetic energy of the gas is 4.678 kJ/mol.

User Sam Mikes
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