Question

In TUV below, find m T to the nearest degree

Answer 1

The guy above me is correct but I'm gonna explain it better

Explanation:

Step ONE 1.- Arrange the equation: Choose an equation from the LAW OF COSINES.

8.1^2= 7.1^2 + 4.2^2 - 2(7.1)(4.2) COS(T)

Step 2- Solve

65.61= 68.05-59.64 x COS(T)

Step 3- Inverse Operation (SUBTRACT: 65.61-68.05)

65.61= 59.64 x COS(T)

-68.05

INVERSE OPERATION AGAIN (DIVIDE: -2.44/59.64)

-2.44/59.64= COS(T)

INVERSE OPERATION ONE LAST TIME

WE MUST GET THE "T" ALONE SO WE MUST MOVE THE "COS" TO THE OTHER SIDE "COS^-1 (Cos (x))

Cos ^-1 (-.04)= (T)

87.707= T

ROUND: ROUND 87.707 TO THE NEAREST DEGREE.

88 = T

Answer 2

T = 88 degrees to the nearest degree

Explanation:

To find the measure of the angle T, we can use the cosine rule

We have the formula as;

t^2 = u^2 + v^2 - 2uv Cos T

t = 8.1

u = 7.1

v = 4.2

8.1^2 = 7.1^2 + 4.2^2 - 2(7.1)(4.2) cos T

-2.44 = -59.64 cos T

cos T = (2.44)/(59.64)

T = arc cos (2.44/59.64)

T = 87.66

to the nearest degree, this is 88 degrees