Question

8a2 + 6a = 5
how do I do this?

Answer 1

`8a^2 + 6a = 5 \\ \\8a^2 + 6a -5 =0\\ \\\Delta = b^(2)-4ac = 6^(2)-4*8* (-5)=36 +160=196\\ \\a_(1)=(-b-√(\Delta ))/(2a) =(-6- √(196))/(2*8)=(-6- 14)/(16)= (-20)/(16)=- (5)/(4)=-1(1)/(4)\\ \\a_(2)=(-b+√(\Delta ))/(2a) =(-6+√(196))/(2*8)=(-6+14)/(16)= (8)/(16)= (1)/(2)`