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Two objects are moving along separate linear paths where each path is described by postion, d, and time, t. The variable d is measured in meters and the variable t is measured in seconds. The equation describing the graph of the postion of the first object with respect to time is d=2.5t+2.2. The graph of the the position of the second object is a parallel line passing through (t=0,d=1). What is the equation of the second graph.

d=2.5t+1
d=-0.4t+1
d=2.5t+3.2

User Balter
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1 Answer

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For the answer to the question above, the linear equation:
d = m t + b
If the graph of the position of the second object is parallel to d = 2.5 t +2.2, than m = 2.5
t = 0, d = 1
1 = 2.5 · 0 + b
b = 1
so the answer is A ) d = 2.5 t + 1
User Kvantour
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