Question

QR,RS , and SQ are midsegments of WXY.

The perimeter of WXY is ____ cm.

Answer 1

Answer: Perimeter of ΔWXY is given by

`XW+XY+WY\\=4.04+4.56+5.86\\=14.46 cm`

Explanation:

Since we have given that

`QR=2.93cm\\RS=2.04cm\\QS=2.28cm`

By using Mid point theorem, "if line joining the midpoints of the any two sides , then this line becomes parallel to the third side and it becomes half of the third side".

So here , if consider firstly Q and R are mid-points of XW and XY then,

QR║WY so,

`WY= 2* QR\\WY=2\Ttimes 2.93\\WY=5.86cm`

Similarly,

QS║XY so,

`XY=2* QS\\XY=2* 2.28\\XY=4.56cm`

Similarly,

RS║XW, so

`XW=2* RS\\XW=2* 2.04\\XW=4.04cm`

Perimeter of ΔWXY is given by

`XW+XY+WY\\=4.04+4.56+5.86\\=14.46 cm`

Answer 2

QR=2.93
RS=2.04
QS=2.28
Add these together to get the perimeter of 7.25...
then use the sides to help you out
BY TAKING QS (2.28) and doubling that to be 4.56 which gives you the length of line segment XY.
RS doubled is 4.08 which is the line segment XW.
QR doubled is 5.58; line segment WY.
Add all 3 values to get 14.22 CM.