Register
What are the real zeros of x3 + 4x2 − 9x − 36?
217k views
1 vote
What are the real zeros of x3 + 4x2 − 9x − 36?

User Kepkin
by
7.2k points

2 Answers

1 vote

Answer:

c. -4, -3, 3

Explanation:


What are the real zeros of x3 + 4x2 − 9x − 36?-example-1
User Mortada
by
7.7k points
6 votes
x3 + 4x2 -9x -36
[x3 + 4x2] -9 [ x+4]
take x2 common factor from first praket
x2[x+4] -9 [x+4]
= [x+4] *[x2 -9]
so the zeros of this equation are -4 , 3, -3
User Ragesh Kr
by
7.8k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.3m questions

10.9m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Write words to match the expression. 24- ( 6+3)
Link Copied!