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What are the real zeros of x3 + 4x2 − 9x − 36?
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What are the real zeros of x3 + 4x2 − 9x − 36?

User Kepkin
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2 Answers

1 vote

Answer:

c. -4, -3, 3

Explanation:


What are the real zeros of x3 + 4x2 − 9x − 36?-example-1
User Mortada
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7.9k points
6 votes
x3 + 4x2 -9x -36
[x3 + 4x2] -9 [ x+4]
take x2 common factor from first praket
x2[x+4] -9 [x+4]
= [x+4] *[x2 -9]
so the zeros of this equation are -4 , 3, -3
User Ragesh Kr
by
8.1k points
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