In a paralleogram oppoaite sides are equal.
AD≅ BC
Or,3r+8=2r+12
Subtracting 2r both sides
3r-2r+8=12
r+8=12
Subtracting 8 both sides r=4.
The sides AB=CD= 4r-2=4(4)-2=16-2=14
Sides AD=BC=3r+8=3(4)+8 =12+8=20.
Perimeter is sum of all the sides.
Perimeter of parallelogram ABCD= AB+BC+CD+DA=14+20+14+20=68
68 feet of fencing are needed to enclose the lot .