Question

Find the inverse of the following function. gx= 1/x-2

Answer 1

In order to find the inverse function of g(x) = 1/x - 2, we just need to switch g(x) for x and x for g-1(x), then we isolate the inverse function g-1(x):

`\begin{gathered} g(x)=(1)/(x)-2 \\ x=(1)/(g^(-1)(x))-2 \\ (1)/(g^(-1)(x))=x+2 \\ g^(-1)(x)=(1)/(x+2) \end{gathered}`

So the inverse function is g-1(x) = 1/(x+2)