Question

An olympic sprinter can go from a state of rest to 11 meters per second in 10 seconds. What is the sprinter's average acceleration?

Answer 1

Since I think the formula for acceleration is a=d/t you plug in 11 for d and 10 for t and get 11/10=1.1 so 1.1 m/s is his/her acceleration.

Answer 2

Answer: Sprinter's average acceleration =
`1.1(m)/(s^2)`

Step-by-step explanation:

The formula for the average acceleration is given as follows:

`\overline{a} = (v_f - v_i)/(\Delta t)` --- (A)

Where,

`v_f` = Final velocity =
`11(m)/(s)`

`v_i` = Initial velocity =
`0(m)/(s)`

`\Delta t` = Elapsed time = 10 seconds

Plug the values in equation (A):

`\overline{a} = (11 - 0)/(10) = 1.1(m)/(s^2)`

Therefore, the sprinter's average acceleration is
`1.1(m)/(s^2)`.