Question

Jerry measured and timed the descent of a diving bell spider in a large fish tank. The spider reached a position 412 412 inches below the surface of the water after descending at a constant rate for 112 112 seconds. Jerry recorded this as −412 −412 inches. What is the position of the spider relative to the surface after 1 second? Enter your answer in the box.

Answer 1

Answer:-3

Step-by-step explanation:i took the test

Answer 2

Step 1

Convert mixed numbers to an improper fractions

`4(1)/(2) =(4*2+1)/(2)= (9)/(2)`

`1(1)/(2) =(1*2+1)/(2)= (3)/(2)`

Step 2

Find the unit rate of the descending

`unit\ rate= ((9/2))/((3/2))=3 (inches)/(sec)`

therefore

the answer is

the position of the spider relative to the surface after
`1` second is
`-3\ inches`