223k views
4 votes
1. Find the value of y so that the line passing through (6, y) and (7, 5) has a slope of -3.

2. Write the equation of a line in point-slope form that has a slope of -1 and passes through the point (-2, 5).

3.Write the equation of a line in slope-intercept form passing through (2, 7) and (-2, 9) y=1/3x+5 and passes through (-9, 5)

5. Write the equation of a line in slope intercept form that is perpendicular to the line y = –4x and passes through the point (2, 6)

6. Write the equation of a line in slope-intercept form that has a slope of and passes through the point (8, -1)

User Komputist
by
8.1k points

1 Answer

2 votes
I believe for some of these you're looking for the equation:
y-y1=m(x-x1)
m being slope
(x1 , y1) being the point

So, using question two for an example,
You will leave x and y as they are and plug in the values you know for m, x1, and y1. 5 for y1 because it is the y value, and -2 for x1 under the same reasoning.
y-5 = -1 (x - (-2))
y-5 = -1 (x + 2)
Solve for parentheses first by distributing the -1
y-5 = -x -2
Add 5 to each side to change its side.
y = -x -2 +5
simplify like numbers by adding 5 and -2
y = -x + 3
This will be your answer for number two

If you give me a moment I'll solve the rest, if you want explanations I can give them as well.


User Kietz
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.