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Suppose the definite integral, bottom value 2, top value 6 of g(x)dx=12 and the definite integral bottom value 5 top value 6 of g(x)dx= -3, find the value of the definite integral bottom value 2 and top
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Suppose the definite integral, bottom value 2, top value 6 of g(x)dx=12 and the definite integral bottom value 5 top value 6 of g(x)dx= -3, find the value of the definite integral bottom value 2 and top value 5 of 3g(x)dx

User DaveG
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The definite integral would be equal to your value from 2 to 6 minus your value from 5 to 6.

12 - (-3) = 15
User M S
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