For the answer to the question above,
(3•(x2))+2x)+(7•(x3)))+(((2•5x2)+6x)+9)
(3•(x2))+2x)+7x3)+(10x2+6x+9)
((3x2 + 2x) + 7x3) + (10x2 + 6x + 9)
7x3+13x2+8x+9 is not a perfect cube.
split the expression at hand into groups, each group having two terms
Group 1: 8x+9
Group 2: 7x3+13x2
then pull out from each group separately.
Group 1: (8x+9) • (1)
Group 2: (7x+13) • (x2)
Find roots (zeroes) of : F(x) = 7x3+13x2+8x+9
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
to make this short,
In this case, the Leading Coefficient is 7 and the Trailing Constant is 9.
The factors of the Leading Coefficient: 1,7
the factors of the Trailing Constant: 1,3 ,9
So the answer is 7x3 + 13x2 + 8x + 9