Question

How to solve this in elimination form:

4y+4=7x
36-4y=3x
And also:
3x-10y-29=0
-11x-10y+13=0

Answer 1

1.

`4y+4=7x \\ \underline{36-4y=3x} \\ 4y+4+36-4y=7x+3x \\ 40=10x \\ x=4 \\ \\ 4y+4=7x \\ 4y+4=7 * 4 \\ 4y+4=28 \\ 4y=24 \\ y=6 \\ \\ x=4 \\ y=6`

2.

`3x-10y-29=0 \\ -11x-10y+13=0 \ \ \ |* (-1) \\ \\ 3x-10y-29=0 \\ \underline{11x+10y-13=0} \\ 3x-10y-29+11x+10y-13=0 \\ 14x-42=0 \\ 14x=42 \\ x=3 \\ \\ 3x-10y-29=0 \\ 3 * 3 -10y-29=0 \\ 9-10y-29=0 \\ -10y-20=0 \\ -10y=20 \\ y=-2 \\ \\ x=3 \\ y=-2`