Question

A ball rolls off of a table (take v0 as 0m/s) that is 1.25m tall. How long does it take for the ball to hit the floor?

Answer 1

Let
h=height of table= 1.25m
g=acceleration due to gravity= 9.8m/s^2
t=time taken=?

Solution
h =(vi)(t)+1/2(g)(t^2)
1.25=(0)(t)+1/2(9.8)(t^2)
t^2 = 0.255
t. = 0.5s