Answer:
T'(0, 3) R'(-6,6) and S'(-3,-6)
Explanation:
The given vertices are
R( 6, 6), S(3, -6), and T(0, 3)
We have to find the image of these vertices
Since T(0, 3) lies on y axis so its image over the y axis will be same T'(0,3)
since R(6, 6) lies in 1st quadrant so image over the y axis will lie in second quadrant and the point will be R'(-6, 6)
Similarly S(3, -6) lies in 4th quadrant of which image will lie in 3rd quadrant having co-ordinates as (-3, -6)
Therefore, T'(0, 3) R'(-6,6) and S'(-3,-6) is the answer.