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A cheetah accelerates from rest at a rate of 5.4 m/s2. How far has the cheetah gone after 1.8 seconds?
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A cheetah accelerates from rest at a rate of 5.4 m/s2. How far has the cheetah gone after 1.8 seconds?

User Frognosis
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2 Answers

3 votes
S = ut + 1/2 *a*t^2 . u=0(since cheetah starts from rest). S = 0 + 1/2 *a*t^2. S= 1/2 *5.4*(1.8)^2 = 8.748m.
User Bobwah
by
8.3k points
5 votes
Us the usual formula,


s=(1)/(2)at^2=0.5\cdot5.4\cdot1.8^2=8.748\ m
User Mohanavel
by
6.9k points
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