Question

A figure skater begins spinning counterclock-

wise at an angular speed of 4.6 7 rad/s. Dur-
ing a 4.2 s interval, she slowly pulls her arms
inward and finally spins at 7.3 7 rad/s.
What is her average angular acceleration
during this time interval?
Answer in units of rad/s.​

Answer 1

Angular acceleration,
`\alpha =0.64\ rad/s^2`

Step-by-step explanation:

Given that,

Initial angular velocity,
`\omega_i=4.67\ rad/s`

The final angular velocity,
`\omega_f=7.37\ rad/s`

Time, t = 4.2 s

We need to find her average angular acceleration during this time interval. Acceleration is the rate of change of velocity. So,

`\alpha =(\omega_f-\omega_i)/(t)\\\\\alpha =(7.37-4.67)/(4.2)\\\\\alpha =0.64\ rad/s^2`

So, her average angular acceleration is
`0.64\ rad/s^2`.