Which is the equation for bc?

Question

asked Nov 7, 2017 39.8k views

2 Answers

MahoriR · Answer 1 · 2017-11-11T10:41:16+0000

Answer:

y(x)=- (4)/(5)x+1=-0.8 x+1

Explanation:

A line can be expressed using a slope-intercept form:

y(x)=mx+b

Where:

$m=Slope=(\Delta y)/(\Delta x) =(y_2-y_1)/(x_2-x_1)$

$b=y-axis\hspace{3}intercept$

Given a point on the line
P(x_1,y_1) it is possible to obtain the previous equation from the following formula:

y-y_1=m(x-x_1)

From the graph we can extract the two points necessary to find the equation. As you can see:

$B(x_1,y_1)=(-5,5)\\C(x_2,y_2)=(0,1)$

So, let's find the slope:

m=(1-5)/(0-(-5))= (-4)/(5) =-0.8

Now, we have everything we need to find the equation for BC:

$y-5=-(4)/(5) (x-(-5))\\\\y-5=-(4)/(5) x-4\\\\y=-(4)/(5)+1=-0.8x+1$

Therefore, the equation for BC is:

y(x)=- (4)/(5)x+1=-0.8 x+1