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During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.82 s, how high does it rise? The acceleration of gravity is 9.8 m/s².
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Mar 4, 2017
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During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.82 s, how high does it rise? The acceleration of gravity is 9.8 m/s².
Physics
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Nikolay Aleshkovskiy
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The answer is 56.98 m
The dislocation (d) is:
d = v1 * t + 1/2 * a * t²
v1 - initial velocity
t - time
a -
acceleration of gravity
We know:
d = ?
v1 = ?
t = 6.82 s / 2 = 3.41 (it reaches the peak at half time)
a = - 9.8 m/s²
Let's first calculate v1:
v2 = v1 + at
v2 - final velocity (v2 = 0 when it reaches peak)
0 = v1 + -9.8 * 3.41
0 = v1 - 33.418
v1 = 33.418 m/s
d = v1 * t + 1/2 * a * t²
d = 33.418 * 3.41 + 1/2 * -9.8 * 3.41²
d = 113.96 - 56.98
d = 56.98 m
PSBeginner
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Mar 10, 2017
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PSBeginner
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