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The monthly rents (in dollars) paid by 7 people are given below.(Note that these are already ordered from least to greatest.)845, 955,985, 995, 1035, 1055, 1095Suppose that one of the people moves. Her rent changes from $845 to $1020.Answer the following.(a) What happens to the median?(6) What happens to the mean?It decreases by siO It increases by soIt stays the same.O It decreases by s.It increases by saO It stays the same.Х5?

The monthly rents (in dollars) paid by 7 people are given below.(Note that these are-example-1
User Ashish P
by
2.1k points

1 Answer

27 votes
27 votes

Let us calculate the mean and median before and after the change in rent.

Before the change:

The mean monthly rent is given by


\operatorname{mean}=\frac{\sum^{}_{}x_i}{n}=(845+955+985+995+1035+1055+1095)/(7)=(6965)/(7)=995

Mean = 995

The median monthly rent is the value in the middle of the data.

Note that the data is already sorted from least to greatest.


\operatorname{median}=((n+1)/(2))^(th)=((7+1)/(2))^(th)=((8)/(2))^(th)=4^(th)\; value

The 4th value in the data set is 995

Median = 995

After the change:

Now, the rent changes from $845 to $1020

So, the data becomes

1020, 955,985, 995, 1035, 1055, 1095

Arrange the data from least to greatest.

955, 985, 995, 1020, 1035, 1055, 1095

The mean monthly rent is given by


\operatorname{mean}=\frac{\sum^{}_{}x_i}{n}=(1020+955+985+995+1035+1055+1095)/(7)=(7140)/(7)=1020

Mean = 1020

The median monthly rent is the value in the middle of the data

955, 985, 995, 1020, 1035, 1055, 1095


\operatorname{median}=((n+1)/(2))^(th)=((7+1)/(2))^(th)=((8)/(2))^(th)=4^(th)\; value

The 4th value in the data set is 1020

Median = 1020

(a) Change in median = 1020 - 995 = +25

It increases by $25

(b) Change in mean = 1020 - 995 = +25

It increases by $25

User BCLtd
by
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