The question requires us to provide the IUPAC name for the structure given.
To determine the IUPAC name of an organic compound, first we need to analyze a few characteristics of the structure, for example: if it is linear or not, if it has ramifications, if it presents double or triple bonds, if it contains homogeneous, if it contains any "special groups" (such as ketone and esthers) etc.
For the structure presented, we can see that it is a linear chain that contains ramifications and only presents simple bonds, thus it is an alkane (the final part of its name must be -ane).
Next, we must find the main chain, which in this case corresponds to the longest sequence of carbons possible. We can see that the structure presented has 9 carbons on its main chain, as highlighted in orange in the image below:
Thus, the name of this compound (still not considering the ramifications) must be "nonane" (9 carbons on the main chain of an alkane).
Next, we must take the ramifications into consideration: there are 3 methyl structures (-CH3) attatched to the main chain (highlighted in blue in the following image):
We must number their position in a way that we achieve the smallest numbers possible. To do that, we can start numbering the main chain from the right to the left, as shown below:
(This way, the sum of the radical positions would be 2+5+6 = 13, instead of 4+5+8=17 that we would obtain numbering the chain from left to right)
Therefore, the methyl groups are bonded to the carbons 2, 5 and 6 from the main chain.
Putting all these information together (alkane with 9 carbons and three methyl groups in the positions 2,5 and 6), we'll have the name 2,5,6-trimethylnonane for the structure given.