Question

Can you please help me and can you show your work please

Answer 1

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Step-by-step explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

`1.5x10^(25)molecules*(1mol)/(6.022x10^(23)molecules) =25 molH_2O`

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

`1.2mol*(40.00g)/(1mol) =41.2g`

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

`45g*(1mol)/(180.15g)=0.25g`

4. Here, since the molar mass of ammonia is 17.03 g/mol:

`20mol*(17.03g)/(1mol)=340.6g`

5. Here, since the molar mass of SO2 is 64.06 g/mol:

`48g*(1mol)/(64.06g) *(6.022x10^(23)molecules)/(1mol) =4.5x10^(23)molecules`

Best regards!