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Suppose that the function h is defined, for all real numbers, as follows.Find h(- 4), h(- 1) , and h(0) .h(x)= -2&if x<=-1\\ (x+1)^ 2 &if-1=2
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Suppose that the function h is defined, for all real numbers, as follows.Find h(- 4), h(- 1) , and h(0) .h(x)= -2&if x<=-1\\ (x+1)^ 2 &if-1=2

Suppose that the function h is defined, for all real numbers, as follows.Find h(- 4), h-example-1
User Kimooz
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12 votes
12 votes

The piecewise function is given as shown below:


h(x)=\begin{cases}{-2,\text{ }if\text{ }x\leq-1} \\ {(x+1)^2,\text{ }if\text{ }-1<strong>QUESTION 1</strong><strong>: h(-4)</strong><p>-4 satisfies the interval:</p>[tex]\begin{gathered} x\leq-1 \\ -4\leq-1 \end{gathered}

Therefore,


h(-4)=-2

QUESTION 2: h(-1)

-1 satisfies the interval:


\begin{gathered} x\leq-1 \\ -1\leq-1 \end{gathered}

Therefore,


h(-1)=-2

QUESTION 3: h(0)

0 satisfies the interval:


\begin{gathered} -1<strong>Therefore,</strong>[tex]\begin{gathered} h(0)=(0+1)^2=1^2 \\ h(0)=1 \end{gathered}

User Geekbuntu
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