Question

The correlation coefficient r between a child age x and the number of minutes spent doing homework each day y is 0.694.

What percent of the variation?

A. 30.6%
B. 48.2%
C. 51.8%
D. 69.4%

Answer 1

The answer is 48.2%

Explanation:

The correlation coefficient r between a child age x and the number of minutes spent doing homework each day y is 0.694 i.e r=0.694

Now, we have to find percent of the variation.

The coefficient of determination is
`r^(2)`

The square of r(correlation coefficient) is the percent of variation that is explained by the dependent variable.

If r=0.694 ⇒
`r^(2)= (0.694)^(2)=0.482` this means that 48.2% of variation in dependent variable.

Answer 2

The final answer to your question is that the percent variation of the correlation coefficient between a child age x and the number of minutes spent doing homework each day y with r = 0.694 is C. 51.8%.

Hope my answer would be a great help for you.