Question

3.Calculate the temperature when 8.5 L at 15.0 °C is compressedto 4.5L.

Answer 1

The temperature is 7.94°C.

Step-by-step explanation:

1st) To calculate the temperature, we can use the Charles's Law.

`(V_1)/(T_1)=(V_2)/(T_2)`

The given information is:

- V1: 8.5L

- T1: 15.0°C

- V2: 4.5L

- T2: this is what we have to calculate:

2nd) Replacing the values in the formula:

`\begin{gathered} (V_1)/(T_1)=(V_2)/(T_2) \\ (8.5L)/(15.0\degree C)=(4.5L)/(T_2) \\ 0.567(L)/(\degree C)=(4.5L)/(T_(2)) \\ T_2=(4.5L)/(0.567(L)/(\degree C)) \\ T_2=7.94\degree C \end{gathered}`

Finally, the temperature is 7.94°C.