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How many molecules are contained in 55.0 g of H2SO4

2 Answers

3 votes
moles of H2SO4 = 55/98 = 0.56mol. Number of molecules of H2SO4 = moles x 6.02 x 10^23 = 0.56 x 6.02 x 10^23 = 3.37 x 10^23. Hope it helps
User Jerven Clark
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8.1k points
7 votes

Answer:
3.37* 10^(23) molecules of
H_2SO_4

Explanation: To calculate the moles, we use the formula:



Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass= 55.0 g

Molar mass= 98g/mol


Moles=(55.0g)/(98g/mol)=0.56moles

1 mole of
H_2SO_4 contains =
6.023* 10^(23) molecules of
H_2SO_4

0.56 moles of
H_2SO_4 contains =
(6.023* 10^(23))/(1)* 0.56=3.37* 10^(23) molecules of
H_2SO_4

User Mtveezy
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7.3k points