Question

A 50.0 g projectile is launched with a horizontal velocity of 657 m/s from a 4.65 kg launcher moving in the same direction at 2.00 m/s. What is the launcher’s velocity after the launch?

Answer 1

The Physics question deals with conservation of momentum to find the velocity of a launcher after firing a projectile. After applying the conservation of momentum principle and substituting the given values, we can calculate the launcher's final velocity.

Step-by-step explanation:

The subject of the question is Physics, specifically focusing on the conservation of momentum and the resulting calculations from it. To find the launcher's velocity after the launch, we apply the conservation of momentum principle, which states that the total momentum of a system remains constant if no external forces act on it. In the given scenario, we can set up the following equation:

Initial momentum = Final momentum

(mprojectile × vprojectile_initial) + (mlauncher × vlauncher_initial) = (mprojectile × vprojectile_final) + (mlauncher × vlauncher_final)

Given:

• mprojectile = 50.0 g
• vprojectile_initial = 657 m/s (horizontal velocity)
• mlauncher = 4.65 kg
• vlauncher_initial = 2.00 m/s

Converting the mass of the projectile to kg (50.0 g = 0.050 kg) and substituting the values into the equation, we can solve for vlauncher_final.
Let's solve:

1. 
   
3. Initial momentum of system = mprojectile × vprojectile_initial + mlauncher × vlauncher_initial
4. 
   
6. (0.050 kg × 657 m/s) + (4.65 kg × 2.00 m/s) = 0 + 4.65 kg × vlauncher_final
7. 
   
9. Solve for vlauncher_final

The launcher's velocity after the launch can be found after the calculations based on the above momentum equation.

Answer 2

backwards with the speed 5.24m/s