Question

Miriam buys 24 petunia plants and 40 azalea plants. She wants to plant an equal number of flowers in each row of her garden. Each row will contain only one type of flowering plant

Part A: determine the greatest number of plants that could be in each row of the garded

Part B: How many rows of each type of flour will be im Miriams garden?

Answer 1

Answer: A. 8

B. There will be 3 rows of petunia plants and 5 rows of azalea plants in Miriam's garden.

Explanation:

Given : Miriam buys 24 petunia plants and 40 azalea plants. She wants to plant an equal number of flowers in each row of her garden.

The greatest number of plants that could be in each row of the garden = greatest common factor of 24 and 40.

Prime factorization of 24 and 40 :-

`24=2*2*2*3\\\\40=2*2*2*5`

The greatest common factor of 24 and 40=
`2*2*2=8`

Thus , the greatest number of plants that could be in each row of the garden= 8

The number of rows of petunia plants =
`(24)/(8)=3`

The number of rows of azalea plants =
`(40)/(8)=5`

Hence, there will be 3 rows of petunia plants and 5 rows of azalea plants in Miriam's garden.

Answer 2

We are given with
24 petunia plants
40 azalea plants

Part A:
Since Miriam wants to plant an equal number of flowers in each row of her garden, we have to find the greatest common factor between 24 and 40
The factors of 24 are 2,2,2,3
The factors of 49 are 2,2,2,5
Therefore, their GCF is 2x2x2 = 8
The greatest number of plants that could be in each row is 8 plants

Part B:
For petunia:
24/8 = 3 rows
For azalea
40/8 = 5 rows