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Two asteroids are 50,000 m apart. one has a mass of 5 x 10^8 kg. If the force of gravity between them is 8.67 x 10 ^ -2 N, what is the mass of the other asteroid?

User ChaoYang
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2 Answers

3 votes
6.5 *10^9 kg
is the mass of the second one
Two asteroids are 50,000 m apart. one has a mass of 5 x 10^8 kg. If the force of gravity-example-1
User Lvsti
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4 votes

Answer:

The mass of the other asteroid is
m_2=6.49* 10^9\ kg.

Step-by-step explanation:

Given that,

Mass of one asteroid,
m=5* 10^8\ kg

The separation between two asteroids, r = 50,000 m

The force of gravity between asteroids,
F=8.67* 10^(-2)\ N

We need to find the mass of the other asteroid. The gravitational force acting between two masses is given by :


F=G(m_1m_2)/(r^2)


m_2 is the mass of other asteroid


m_2=(Fr^2)/(Gm_1)


m_2=(8.67* 10^(-2)* (50000)^2)/(6.67* 10^(-11)* 5* 10^8)


m_2=6.49* 10^9\ kg

So, the mass of the other asteroid is
m_2=6.49* 10^9\ kg. Hence, this is the required solution.

User Amogh Talpallikar
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