Question

If p(x) = x2 – 1 and q(x)=5(x-1) , which expression is equivalent to (p – q)(x)?

Answer 1

easy
that just means p(x)-q(x)=
x²-1-(5(x-1))=
x²-1-5(x-1)=
x²-1-5x+5=
x²-5x+4
(which factors to (x-4)(x-1) btw)

Answer 2

Answer: The required equivalent expression is
`x^2-5x+4.`

Step-by-step explanation: We are given the following two functions :

`p(x)=x^2\\\\q(x)=5(x-1).`

We are to find the expression equivalent to (p - q)(x).

We know that

for any two functions f(x) and g(x),

`(f-g)(x)=f(x)-g(x).`

Therefore, we get

`(p-q)(x)\\\\=p(x)-q(x)\\\\=(x^2-1)-(5x-5)\\\\=x^2-1-5x+5\\\\=x^2-5x+4.`

Thus, the required equivalent expression is
`x^2-5x+4.`