Question

How many grams of sulfur trioxide are produced 18 mol O2 react with sufficient sulfur? Show all your work S8 +12O 2> 8SO3

Answer 1

`m_(SO_3)=2.31x10^4gSO_3`

Step-by-step explanation:

Hello!

In this case, since the reaction between sulfur and oxygen is:

`S_8 +(1)/(2) O_2 \rightarrow 8SO_3`

Whereas there is a 1/2:8 mole ratio between oxygen and SO3, and we can compute the produced grams of product as shown below:

`m_(SO_3)=18molO_2*(8molSO_3)/(1/2molO_2) *(80.06gSO_3)/(1molSO_3) \\\\m_(SO_3)=23,057.3gSO_3=2.31x10^4gSO_3`

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