Question

The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1). Find the midpoint of line HJ

Answer 1

(5,2) - midpoint ...

Answer 2

(5,2)

Explanation:

It is given that The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1).

Now, the mid point is given as:

`M=((x_(1)+x_(2))/(2),(y_(1)+y_(2))/(2))`

Then, the mid point of HJ having coordinates H(3, 5), and J(7, -1)is:

`M=((3+7)/(2),(5+(-1))/(2))`

`M=((3+7)/(2),(5-1)/(2))`

`M=((10)/(2),(4)/(2))`

`M=(5,2)`

Therefore, the mid point of HJ is (5,2).