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The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1). Find the midpoint of line HJ

User Mathewc
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(5,2) - midpoint ...
User Jic
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Answer:

(5,2)

Explanation:

It is given that The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1).

Now, the mid point is given as:


M=((x_(1)+x_(2))/(2),(y_(1)+y_(2))/(2))

Then, the mid point of HJ having coordinates H(3, 5), and J(7, -1)is:


M=((3+7)/(2),(5+(-1))/(2))


M=((3+7)/(2),(5-1)/(2))


M=((10)/(2),(4)/(2))


M=(5,2)

Therefore, the mid point of HJ is (5,2).

User Tbielaszewski
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