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A train needs 4 hours to go from the first station to the second. If the third station is 120 miles away and the total travel time must be no more than 7 hours, write an inequality that would let you find the slowest average speed, v, the train could have.

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the answer is

v= D/T, T <=7-4=3
so T=D/v

3>=120/v implies v>=120/3=40mph
finally v>=40mph
User Aruanoc
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